answer：Okay, so I have this problem about buying vegetable seedlings for a school's labor education program. They want to buy two types, A and B. The problem says that the price of each bundle of type A is twice the price of type B. Also, with 400 yuan, you can buy 10 fewer bundles of type A compared to type B. I need to find the price of each bundle of type A seedlings.Alright, let's break this down. First, I'll assign variables to make it easier. Let me call the price of type B seedlings "x" yuan per bundle. Since type A is twice as expensive, that would make the price of type A seedlings "2x" yuan per bundle.Now, the next part says that with 400 yuan, you can buy 10 fewer bundles of type A than type B. So, if I think about how many bundles you can buy, it's the total money divided by the price per bundle. For type B, that would be 400 divided by x, which is 400/x bundles. For type A, it's 400 divided by 2x, which simplifies to 200/x bundles.According to the problem, the number of type A bundles is 10 less than type B bundles. So, I can write an equation: 400/x - 200/x = 10. Let me check that. Yes, that makes sense because 400/x is the number of type B bundles, and 200/x is the number of type A bundles, and their difference is 10.Simplifying the equation: 400/x - 200/x = 10. Combining the terms gives me 200/x = 10. To solve for x, I can multiply both sides by x, which gives 200 = 10x. Then, dividing both sides by 10, I get x = 20.So, the price of type B seedlings is 20 yuan per bundle. Since type A is twice that, it should be 2 times 20, which is 40 yuan per bundle.Wait, let me double-check to make sure I didn't make a mistake. If type B is 20 yuan, then with 400 yuan, I can buy 400/20 = 20 bundles of type B. For type A, at 40 yuan per bundle, 400/40 = 10 bundles. And indeed, 20 - 10 = 10, which matches the problem statement. So, it seems correct.I think I've got it. The price of each bundle of type A seedlings is 40 yuan.

answer：First, I need to determine the average points Clayton scored in the first three games. I'll start by adding up the points from each of these games.10 points (first game) + 14 points (second game) + 6 points (third game) = 30 pointsNext, I'll calculate the average by dividing the total points by the number of games.30 points / 3 games = 10 points per gameIn the fourth game, Clayton scored this average, which is 10 points.Finally, I'll add the points from all four games to find the total points Clayton scored.30 points (first three games) + 10 points (fourth game) = 40 pointsTherefore, Clayton scored a total of 40 points during the first four games.

answer：Alright, so I have this math problem here: (3 - (-3)^{3 - (-1)}). Hmm, okay, let me try to figure this out step by step. I remember that when dealing with exponents and parentheses, I need to follow the order of operations, which is parentheses first, then exponents, followed by multiplication and division, and finally addition and subtraction. First, I should look at the exponent part: (3 - (-1)). Wait, that's inside the exponent of (-3). So, let me solve that first. Subtracting a negative is like adding a positive, right? So, (3 - (-1)) becomes (3 + 1), which equals 4. Okay, so now the expression simplifies to (3 - (-3)^4).Next, I need to calculate ((-3)^4). I recall that when you raise a negative number to an even power, the result is positive, and when you raise it to an odd power, it remains negative. Since 4 is an even number, ((-3)^4) should be positive. Let me compute that: (-3) multiplied by itself four times. So, (-3 times -3 = 9), then (9 times -3 = -27), and finally (-27 times -3 = 81). Okay, so ((-3)^4 = 81). Now, substituting that back into the expression, I have (3 - 81).Finally, subtracting 81 from 3 gives me (3 - 81 = -78). So, the result of the expression (3 - (-3)^{3 - (-1)}) is (-78).Let me double-check to make sure I didn't make any mistakes. I first simplified the exponent part correctly: (3 - (-1) = 4). Then, I calculated ((-3)^4 = 81). Subtracting that from 3 gives (-78). Yeah, that seems right. I don't think I missed anything here.

answer：First, I need to find the divisor ( D ) based on the given information.From the first division, dividing 23 by ( D ) gives a quotient of 5 and a remainder of 3. This can be written as:[23 = 5D + 3]Solving for ( D ):[23 - 3 = 5D 20 = 5D D = frac{20}{5} D = 4]To verify, I'll check the second division where another number ( N ) is divided by the same divisor ( D ), resulting in a quotient of 7 and a remainder of 5:[N = 7D + 5]Substituting ( D = 4 ):[N = 7 times 4 + 5 = 28 + 5 = 33]This confirms that the divisor ( D ) is indeed 4.

answer：Okay, so I have this problem about forming an emergency medical team. Let me try to understand it step by step. There are two groups: Group A and Group B. - Group A has 4 nurses and 1 doctor.- Group B has 6 nurses and 2 doctors.We need to form a team by selecting 2 members from each group. So, in total, we'll have 4 members in the team. The condition is that the team should have exactly 1 doctor. Alright, so I need to figure out how many different ways we can select these 4 members with exactly 1 doctor. The options given are A: 130, B: 132, C: 315, D: 360. Hmm, okay. Let me break this down. Since we need exactly 1 doctor in the team, this doctor can either come from Group A or Group B. So, there are two scenarios to consider:1. The doctor is from Group A.2. The doctor is from Group B.I'll handle each scenario separately and then add the results together to get the total number of ways.**Scenario 1: Doctor from Group A**Group A has 1 doctor and 4 nurses. We need to select 2 members from Group A, and since we want exactly 1 doctor in the entire team, we'll select 1 doctor and 1 nurse from Group A.- Number of ways to choose 1 doctor from Group A: Since there's only 1 doctor, there's only 1 way to choose the doctor. - Number of ways to choose 1 nurse from Group A: There are 4 nurses, so the number of ways is 4 choose 1, which is 4.So, the number of ways to select 2 members from Group A with exactly 1 doctor is 1 * 4 = 4 ways.Now, moving on to Group B. Since we've already selected 1 doctor from Group A, we need to ensure that the remaining member from Group B is a nurse. Because we need exactly 1 doctor in the entire team, we can't select any doctors from Group B.Group B has 6 nurses and 2 doctors. We need to select 2 members from Group B, but both must be nurses.- Number of ways to choose 2 nurses from Group B: This is 6 choose 2. Calculating that: 6! / (2! * (6-2)!) = (6*5)/(2*1) = 15 ways.So, for Scenario 1, the total number of ways is the product of the ways from Group A and Group B: 4 * 15 = 60 ways.**Scenario 2: Doctor from Group B**Now, let's consider the case where the doctor is from Group B. This means we won't select any doctors from Group A.Group A has 4 nurses. We need to select 2 members from Group A, and since we can't have any doctors, both must be nurses.- Number of ways to choose 2 nurses from Group A: 4 choose 2.Calculating that: 4! / (2! * (4-2)!) = (4*3)/(2*1) = 6 ways.Now, moving to Group B. We need to select 2 members from Group B, and exactly 1 of them should be a doctor (since we need exactly 1 doctor in the entire team).Group B has 2 doctors and 6 nurses.- Number of ways to choose 1 doctor from Group B: 2 choose 1 = 2 ways. - Number of ways to choose 1 nurse from Group B: 6 choose 1 = 6 ways.So, the number of ways to select 2 members from Group B with exactly 1 doctor is 2 * 6 = 12 ways.Therefore, for Scenario 2, the total number of ways is the product of the ways from Group A and Group B: 6 * 12 = 72 ways.**Total Number of Ways**Now, to get the total number of ways to form the team with exactly 1 doctor, we add the results from both scenarios:- Scenario 1: 60 ways- Scenario 2: 72 waysTotal = 60 + 72 = 132 ways.So, the total number of different ways to select 4 members with exactly 1 doctor is 132 ways.**Final Answer**The correct answer is boxed{B}.

answer：Okay, so Jennifer wants to share her sweets with her three friends. That means there are four people in total who will be getting sweets. She has three different colors of sweets: green, blue, and yellow. The quantities are 212 green sweets, 310 blue sweets, and 502 yellow sweets. First, I need to figure out the total number of sweets Jennifer has. To do that, I'll add up all the sweets of each color. So, 212 green plus 310 blue plus 502 yellow. Let me do that calculation: 212 plus 310 is 522, and then 522 plus 502 is 1024. So, in total, Jennifer has 1024 sweets.Now, since she's sharing these sweets equally among herself and her three friends, that makes four people in total. To find out how many sweets each person gets, I need to divide the total number of sweets by the number of people. So, 1024 divided by 4. Let me do that division: 1024 divided by 4 equals 256. Wait, does that mean each person gets 256 sweets? That seems right because 4 times 256 is 1024, which matches the total number of sweets. So, yes, each person, including Jennifer, will get 256 sweets each. I think that's the answer. Each of the four people gets 256 sweets. It looks like the distribution is equal, so no one gets more or fewer sweets than the others. That seems fair.